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-4.9x^2+29x-13=0
a = -4.9; b = 29; c = -13;
Δ = b2-4ac
Δ = 292-4·(-4.9)·(-13)
Δ = 586.2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(29)-\sqrt{586.2}}{2*-4.9}=\frac{-29-\sqrt{586.2}}{-9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(29)+\sqrt{586.2}}{2*-4.9}=\frac{-29+\sqrt{586.2}}{-9.8} $
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